To study the Esterification reaction between alcohol and carboxylic acid
Esterification is the interaction of an organic acid (RCOOH) with an alcohol (ROH) to produce an ester (RCOOR) and water, or a chemical reaction that has at least one ester product.
When alcohol and a carboxylic acid undergo esterification, an ester is formed. Carboxylic acid reacts with alcohols in the presence of concentrated H2SO4 to form esters, resulting in the loss of water molecules. When ethanoic acid reacts with ethanol, for example, the ethyl ethanoate ester is formed. Because it is fruity, the aroma of ester differs from that of carboxylic acid and alcohol.
COOH+R’OH → RCOOR'+H2O
A compound is generated when primary alcohol is reacted with a carboxylic acid in the presence of sulphuric acid. This substance has a sweet smell. Ester is the name given to the resulting chemical. The esterification process is the chemical reaction that occurs during the creation of the ester.
CH3COOH + CH3CH2COOH → CH3COOCH2CH
RCOOH+R'OH → RCOOR'+H2O
Step 1: The formation of cation.
Step 2: Delocalized Carbocation
Step 3: Transfer of proton
Step 4: Formation of pi-Bond
Step 5: Ester formation